2x[3x-(4x-1)]=8x

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Solution for 2x[3x-(4x-1)]=8x equation:


Simplifying
2x[3x + -1(4x + -1)] = 8x

Reorder the terms:
2x[3x + -1(-1 + 4x)] = 8x
2x[3x + (-1 * -1 + 4x * -1)] = 8x
2x[3x + (1 + -4x)] = 8x

Reorder the terms:
2x[1 + 3x + -4x] = 8x

Combine like terms: 3x + -4x = -1x
2x[1 + -1x] = 8x
[1 * 2x + -1x * 2x] = 8x
[2x + -2x2] = 8x

Solving
2x + -2x2 = 8x

Solving for variable 'x'.

Reorder the terms:
2x + -8x + -2x2 = 8x + -8x

Combine like terms: 2x + -8x = -6x
-6x + -2x2 = 8x + -8x

Combine like terms: 8x + -8x = 0
-6x + -2x2 = 0

Factor out the Greatest Common Factor (GCF), '-2x'.
-2x(3 + x) = 0

Ignore the factor -2.

Subproblem 1

Set the factor 'x' equal to zero and attempt to solve: Simplifying x = 0 Solving x = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x = 0

Subproblem 2

Set the factor '(3 + x)' equal to zero and attempt to solve: Simplifying 3 + x = 0 Solving 3 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + x = 0 + -3 Combine like terms: 3 + -3 = 0 0 + x = 0 + -3 x = 0 + -3 Combine like terms: 0 + -3 = -3 x = -3 Simplifying x = -3

Solution

x = {0, -3}

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